In c++ how do i get a 4 digit year to show up as 2 digits....ex, i want january 1 2367 to be 01/01/67...?

i keep getting 01/01/2367....i need to get 01/01/67





date T; // variable of new class date


T.setdate(1,1,2367);





void date::printconventional()


{


if ( month %26lt; 10)


cout %26lt;%26lt; "0";


else


cout %26lt;%26lt; "";


cout %26lt;%26lt; month %26lt;%26lt; "/";





if ( day %26lt; 10)


cout %26lt;%26lt; "0";


else


cout %26lt;%26lt; "/";


cout %26lt;%26lt; day;


if (year


if ( year %26lt; 10)


cout %26lt;%26lt; "0";


else


cout %26lt;%26lt; "/";


cout %26lt;%26lt; year;





// cout %26lt;%26lt; ( month %26lt; 10 ? "0" / "" ) %26lt;%26lt; month %26lt;%26lt; ":"


// %26lt;%26lt; ( day %26lt; 10 ? "0" / "" ) %26lt;%26lt; day;


}

In c++ how do i get a 4 digit year to show up as 2 digits....ex, i want january 1 2367 to be 01/01/67...?
Use modulo operator:





year % 100





If year is 2367, then 2367 modulo 100 is 67.
Reply:use the setprecision code. See source for examples.

strawberry