Change C++ Program?

I need to write a program that will calucate how many quarters, dimes, nickels, and pennies a certain amount of cents will have. So for example, you enter 90 cents. That would be 3 quarters, 1 dime, 1 nickel, 0 pennies. I have this so far, im having trouble with the MATH part. The only thing working is the quarters.





#include %26lt;iostream.h%26gt;





main()


{


int quarters;


int dimes;


int nickels;


int pennies;


int number;





cout %26lt;%26lt; "Enter a number. " %26lt;%26lt; '\n';


cin %26gt;%26gt; number;





quarters = number / 25;


dimes = number - (quarters * 25) / 10;


nickels = number - (quarters * 25) / (dimes * 10) / 5;


pennies = number - (quarters * 25) / (dimes * 10) / (nickels * 5);





cout %26lt;%26lt; "Quarters - " %26lt;%26lt; quarters %26lt;%26lt; '\n';


cout %26lt;%26lt; "Dimes - " %26lt;%26lt; dimes %26lt;%26lt; '\n';


cout %26lt;%26lt; "Nickels - " %26lt;%26lt; nickels %26lt;%26lt; '\n';


cout %26lt;%26lt; "Pennies - " %26lt;%26lt; pennies %26lt;%26lt; '\n';


cout %26lt;%26lt; '\n';


system("PAUSE");


return 0;


}

Change C++ Program?
OK, let's break this up a bit:





Quarters


-----------


Your calculation for quarters was fine.








Dimes


----------


You must not forget the order of operations for mathematical computations. Division happens before subtraction. Try something more like this:





dimes = (number - (quarters * 25)) / 10;








Nickels


----------


You should add together the number of cents present in the quarters and dimes before subtracting them from the number, like this:





nickels = (number - ((quarters * 25) + (dimes * 10)) / 5;








Pennies


------------


For pennies, just subtract out the number of cents used in the quarters, dimes, and nickels.





pennies = number - ((quarters * 25) + (dimes * 10) + (nickels * 5));








That's my suggestion. Hope this helps. As an alternative, you could get the modula of the nickels calculation to get the pennies as well, like so:





pennies = (number - ((quarters * 25) + (dimes * 10)) % 5;