Plz point out the problem with the following code in C++?

#include%26lt;iostream.h%26gt;


#define n 8





void disp(int[]);





void main()


{


int a[n]={1,2,3,4,5,6,7,8};





int i, j, k=1;





i=n/2;





j=i;





k=j-1;





int save=a[n-2];





cout%26lt;%26lt;save%26lt;%26lt;" "%26lt;%26lt;a[n-3]%26lt;%26lt;endl;





disp(a);





cout%26lt;%26lt;endl;





cout%26lt;%26lt;save%26lt;%26lt;"a"%26lt;%26lt;endl;//correct value upto his point.





while(i%26gt;0)





{


cout%26lt;%26lt;"**** save *****"%26lt;%26lt;save %26lt;%26lt;endl;


a[i+i]=a[i];





i--;





}





cout%26lt;%26lt;save%26lt;%26lt;"b"%26lt;%26lt;endl;//value changes here. why?





while(j%26lt;n)


{


a[j-k]=a[j];





j++;





k--;





}





cout%26lt;%26lt;save%26lt;%26lt;" "%26lt;%26lt;a[n-3]%26lt;%26lt;endl;





a[n-3]=save;





disp(a);





}





void disp(int a[])


{


for(int i=0; i%26lt;n; i++)


{


cout%26lt;%26lt;a[i];





}





}

Plz point out the problem with the following code in C++?
I have just compiled and executed your program. The value of "save" does not change. So what's your problem exactly?
Reply:the problem that is causing problem is value of n


the alternative to use it is


redefine the disp(a[])function by disp(int a[],int size_of_a)


which will be the size of array a


but it is of quite consideration the value of save is not changing if you could explain what the purpose of program is i may provide better answer
Reply:You will never get what you wants due to bad indentation. Good luck!