I want to compare 5 integers in c++ but i don't know how to do that .I know how to compare two values but for more than that the code does not yield any result and I just get the cout%26lt;%26lt;whatever is typed%26lt;%26lt;endl;
I would be grateful if you send me the syntax
Does any body know how I can compare more than 2 integers in c++ to get the largest and smallest value?
buddy i dnt know exactly about c++ bt try the following,may b it wll work,so here it goes
first input all the five nos from user or declare 5 nos in a,b,c,d,e,
if(a%26gt;b %26amp;%26amp; a%26gt;c %26amp;%26amp; a%26gt;d %26amp;%26amp; a%26gt;e)
cout%26lt;%26lt;a;
else if(b%26gt;a %26amp;%26amp; b%26gt;c %26amp;%26amp; b%26gt;d %26amp;%26amp; b%26gt;e)
cout%26lt;%26lt;b;
else if(c%26gt;a %26amp;%26amp; c%26gt;b %26amp;%26amp; c%26gt;d %26amp;%26amp; c%26gt;e)
cout%26lt;%26lt;c;
else if(d%26gt;a %26amp;%26amp; d%26gt;b %26amp;%26amp; d%26gt;c %26amp;%26amp; d%26gt;e)
cout%26lt;%26lt;d;
else
cout%26lt;%26lt;e;
this will give the largest no.,similarly you can do for smallest by changing the compare sign.
all the best!
Reply:it just happens when I am trying to compare 3 integers .when I compare 4 the result is correct. I will send you the code and maybe you can compile it yourself to see the result.if find out the cause let me know.
regards Report It
Reply:#include%26lt;iostream%26gt;
using namespace std;
int main()
{
int a,b,c;
cout%26lt;%26lt; "enter three integer to compare "%26lt;%26lt;endl;
cin%26gt;%26gt;a%26gt;%26gt;b%26gt;%26gt;c;
if (a%26gt;b,a%26gt;c)
cout%26lt;%26lt;a%26lt;%26lt;" is the largest"%26lt;%26lt;endl; Report It
Reply:else if (b%26gt;a,b%26gt;c)
cout%26lt;%26lt;b%26lt;%26lt;" is the largest "%26lt;%26lt;endl;
else
cout%26lt;%26lt;c%26lt;%26lt; " is thelargest"%26lt;%26lt;endl;
system("pause");
return 0;
} Report It
Reply:Using STL is the easiest way
#include %26lt;iostream%26gt;
#include %26lt;algorithm%26gt;
using namespace std;
int main()
{
int a[ ] = { 4, 5, 88, 37, 96}; //no matter how many integers
cout %26lt;%26lt; max_element(a[0], a[4]) %26lt;%26lt; endl; //output the maxi
cout %26lt;%26lt; min_element(a[0], a[4] ) %26lt;%26lt; endl; //output the minimum
return 0;
}
Reply:Bubble Sort (works very slow)
void bubbleSort(int numbers[], int array_size)
{
int i, j, temp;
for (i = (array_size - 1); i %26gt;= 0; i--)
{
for (j = 1; j %26lt;= i; j++)
{
if (numbers[j-1] %26gt; numbers[j])
{
temp = numbers[j-1];
numbers[j-1] = numbers[j];
numbers[j] = temp;
}
}
}
}
Quck sort
void quickSort(int numbers[], int array_size)
{
q_sort(numbers, 0, array_size - 1);
}
void q_sort(int numbers[], int left, int right)
{
int pivot, l_hold, r_hold;
l_hold = left;
r_hold = right;
pivot = numbers[left];
while (left %26lt; right)
{
while ((numbers[right] %26gt;= pivot) %26amp;%26amp; (left %26lt; right))
right--;
if (left != right)
{
numbers[left] = numbers[right];
left++;
}
while ((numbers[left] %26lt;= pivot) %26amp;%26amp; (left %26lt; right))
left++;
if (left != right)
{
numbers[right] = numbers[left];
right--;
}
}
numbers[left] = pivot;
pivot = left;
left = l_hold;
right = r_hold;
if (left %26lt; pivot)
q_sort(numbers, left, pivot-1);
if (right %26gt; pivot)
q_sort(numbers, pivot+1, right);
}
There are few more and all have their own advantages, disadvantages. Example: Speed vs. amount of memory used etc etc. Depending on your big O requirement use what's needed.
Reply:int nominal = all[0], answer;
// the five numbers are all[]
for (int x = 1; x %26lt; 5; x++) if (nominal %26gt; all[x]) nominal = all[x];
answer = nominal;
// answer is smallest by now.
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