Shortening this C++ program?

#include %26lt;cstdlib%26gt;


#include %26lt;iostream%26gt;


#include %26lt;cmath%26gt;


#include %26lt;ctime%26gt;


using namespace std;


using std::srand;





int main(int argc, char *argv[])


{


float b, n, wa, ga, ra, ta, tries;





cout %26lt;%26lt; "This is slots"%26lt;%26lt;endl;


ta = 1000;


cout %26lt;%26lt; "You have " %26lt;%26lt; ta %26lt;%26lt; " tokens" %26lt;%26lt;endl;


n = 10;


while (n %26gt; 0)


{


cout %26lt;%26lt; "you can play " %26lt;%26lt; n %26lt;%26lt; " times" %26lt;%26lt;endl;


cout %26lt;%26lt; "How much do want to wager:";


cin %26gt;%26gt; wa;





while (wa %26gt; ta)


{


cout %26lt;%26lt; "That is not a valid wager" %26lt;%26lt; endl;


cout %26lt;%26lt; "enter a valid wager:" %26lt;%26lt; endl;


cin %26gt;%26gt; wa;


}





while (wa %26lt;= ta - ta)


{


cout %26lt;%26lt; "That is not a valid wager" %26lt;%26lt; endl;


cout %26lt;%26lt; "enter a valid wager:" %26lt;%26lt; endl;


cin %26gt;%26gt; wa;


}

Shortening this C++ program?
since the two while conditions do the same thing, combine them into one condition:





while(wa %26gt; ta || wa %26lt;=ta-ta)


{


cout %26lt;%26lt; "that is not a valid wager." %26lt;%26lt;endl;


cout%26lt;%26lt; "Enter a valid wager."%26lt;%26lt;endl;


cin %26gt;%26gt;wa;


}





And then combine your other conditions:





if(ga %26lt; 1 || ga %26gt; 10)


{


cout %26lt;%26lt;"That is not between 1 and 10" %26lt;%26lt;endl;


cout %26lt;%26lt;"Enter a value between 1 and 10" %26lt;%26lt;endl;


cin %26gt;%26gt; ga;


}